직각 펄스  의 임펄스 응답이 다음과 같은 LTI 시스템의 입력일 때,

출력 을 구해보자.

ex2_7.cem

% x(n)=[u(n)=u(n-10]; h(n)=(0.9)^n*u(n)
% y(n)=10*(1-(0.9)^(n+1))*(u(n)-u(n-10))+% (10*(1-(0.9)^10)*(0.9)^(n-9))*u(n-10)
n = -5:50:1;
u1 = stepseq(0,-5,50); u2=stepseq(10,-5,50);
% input x(n)
x = u1-u2;
% impulse response h(n)
h = ((0.9).^(n)).*u1;
%subplot(1,1,1)
subplot(2,1,1); stem(n,x); axis([-5,50,0,2])title("Input Sequence");
xlabel("n"); ylabel("x(n)");
subplot(2,1,2); stem(n,h); axis([-5,50,0,2])title("Impulse Response");
xlabel("n"); ylabel("h(n)"); 
%pause% print -deps2 ex0205a.eps% output response
y = (10*(1-(0.9).^(n+1))).*(u1-u2)+(10*(1-(0.9)^10)*(0.9).^(n-9)).*u2;
%subplot(1,1,1)
subplot(2,1,2); stem(n,y); axis([-5,50,0,8])title("Output Sequence");
xlabel("n"); ylabel("y(n)");